16x+8x^2=960

Solution for 16x+8x^2=960 equation:

16x+8x^2=960

We move all terms to the left:

16x+8x^2-(960)=0

a = 8; b = 16; c = -960;
Δ = b2-4ac
Δ = 162-4·8·(-960)
Δ = 30976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{30976}=176$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-176}{2*8}=\frac{-192}{16}
=-12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+176}{2*8}=\frac{160}{16}
=10
$